A drop of oil of 10^10m spread out on water to make a circular film of radius 10^1m. What is the thickness of the film.
you mean 10^10 m^3 ???????
that is like HUGE, no way, typo
but in general
volume = area* thickness
V = pi R^2 t
t = V/(pi R^2)
I don't know please help me out
geez - just plug in your numbers. You have V,R, and pi, right?
To determine the thickness of the film, we need to use the formula for the volume of a cylinder, as the oil drop will spread out and form a circular film that can be considered as a cylinder shape.
The formula for the volume of a cylinder is given by:
Volume = π * radius^2 * height.
In this scenario, the radius of the circular film is given as 10^1m. Since the oil drop spreads out evenly on the water, we can assume that the thickness of the oil film is equivalent to the height of the cylinder.
Let's substitute the given values into the formula:
Volume = π * (10^1m)^2 * height
We know that the volume of the oil is the product of its initial volume (before spreading) and the ratio of its final volume (after spreading) to the initial volume. Mathematically:
Volume = Initial volume * (Final volume / Initial volume)
The initial volume can be calculated as the volume of a sphere with a radius of 10^10m:
Initial volume = (4/3) * π * (10^10m)^3
The final volume can be calculated as the volume of a cylinder with a radius of 10^1m:
Final volume = π * (10^1m)^2 * height
Substituting these values into the equation, we get:
(4/3) * π * (10^10m)^3 * (Final volume / Initial volume) = π * (10^1m)^2 * height
We can solve for the height (thickness of the film) by rearranging the equation:
height = [(4/3) * (10^10m)^3 * (Final volume / Initial volume)] / (10^1m)^2
Now, we can plug in the given values and perform the calculation to find the thickness of the film.