A bullet is fired with an initial velocity 300m per second.at an angle 30degree.find the horizontal and vertical component of its velocity
I assume 30 deg up from horizontal
component of a vector in any direction is magnitude times cosine of angle to direction
so
horizontal 300 cos 30
vertical 300 cos 60 = 300 sin 30
To find the horizontal (x-component) and vertical (y-component) of the velocity of the bullet, we can use trigonometry.
Given:
Initial velocity of the bullet (v) = 300 m/s
Angle of projection (θ) = 30 degrees
Step 1: Calculate the horizontal component (vx):
The horizontal component is given by vx = v * cos(θ).
vx = 300 * cos(30)
Step 2: Calculate the vertical component (vy):
The vertical component is given by vy = v * sin(θ).
vy = 300 * sin(30)
Step 3: Simplify the values:
Using the values from above:
vx = 300 * cos(30) ≈ 259.81 m/s (rounded to 2 decimal places)
vy = 300 * sin(30) ≈ 150 m/s (rounded to 2 decimal places)
Therefore, the horizontal component of the velocity is approximately 259.81 m/s, and the vertical component of the velocity is approximately 150 m/s.