how many ml of HCl 1 mol required to prepare 1 ltr of 0.1 N HCl
how to prepare phenol phethalene indicator
how to prepare 0.1N of Potassium Permanganate
how to prepare 250 ml of 0.1N sodium Thiosulphate solution
how many ml of HCl 1 mol required to prepare 1 ltr of 0.1 N HCl
Dilute by 10 so take 100 mL of the 1 M, place in a 1 L volumetric flask, add water to the mark, shake, stopper.
how to prepare phenol phethalene indicator
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how to prepare 0.1N of Potassium Permanganate
how to prepare 250 ml of 0.1N sodium Thiosulphate solution
For both of these you need to know the reaction first
To determine the number of milliliters (ml) of HCl 1 mol required to prepare 1 liter (ltr) of 0.1N HCl, you need to perform a calculation using the equation for molarity:
Molarity (M) = moles of solute / volume of solution (in liters)
Here's how you can calculate it step by step:
Step 1: Convert the desired molarity of the HCl solution to moles per liter (mol/L):
0.1 N (normality) is equal to 0.1 moles of HCl per liter of solution.
Step 2: Determine the number of moles of HCl required:
To find the number of moles, multiply the desired molarity by the volume in liters:
0.1 mol/L x 1 L = 0.1 moles of HCl required.
Step 3: Convert moles of HCl to milliliters:
Since the question asks for the volume of HCl in milliliters, you need to convert the number of moles to milliliters.
Remember that 1 liter is equal to 1000 milliliters, so you can use this conversion factor:
1 L = 1000 ml
0.1 moles x (1000 ml / 1 L) = 100 ml
Therefore, 100 milliliters (ml) of HCl 1 mol is required to prepare 1 liter (ltr) of 0.1N HCl.