solve 5a-2b=14 4a+2b=14
5a-2b=14
4a+2b=14
add and you get
9a = 28
a = 28/9
so, b = 7/9
To solve the system of equations:
5a - 2b = 14 ...(Equation 1)
4a + 2b = 14 ...(Equation 2)
We can use the method of elimination to find the values of 'a' and 'b'.
Step 1: Add Equation 1 and Equation 2 to eliminate the 'b' term:
(5a - 2b) + (4a + 2b) = 14 + 14
Simplifying both sides gives:
9a = 28
Step 2: Divide both sides of the equation by 9 to solve for 'a':
9a/9 = 28/9
a = 28/9
Step 3: Substituting the value of 'a' back into Equation 1, we can find 'b':
5(28/9) - 2b = 14
140/9 - 2b = 14
140/9 - 14 = 2b
(140 - 126)/9 = 2b
14/9 = 2b
Step 4: Divide both sides of the equation by 2 to solve for 'b':
(14/9) / 2 = b
14/18 = b
7/9 = b
Therefore, the solution to the system of equations is a = 28/9 and b = 7/9.