abc is an isosceles triangle in which ab=ac=5cm and bc=6cm.calculate am,where m is the mid point of bc show your workings?
am forms a right triangle amc with mc = 3 and ac = 5
am^2 + 3^2 = 5^2
am = 4
In order to find the length of [AM], you want to look at only half of this triangle. Half of an isosceles triangle is a right angle triangle! Therefore you can use Pythagorean theory:
a^2 + b^2 = c^2 (hypotenuse)
That's correct! So the length of AM is 4 cm.
ABC is an isosceles triangle in which /AB/ /AC/=5 and /
BC/ =6.calcultae /AM/, where M is the mid point of BC
mc=3 and ac=5
am^2+3^2=5^2
am=4