Mr. Williams just finished grading his science exams. The class average score on his exam was 79%. However, he forgot to grade John's paper. John scored an 86% on the exam. What is going to happen to the class average, once he includes John's score?
A. The class average will stay the same.
B. There is not enough information.
C. The class average will go up.
D. The class average will go down.
And your answer is?
hint: John's score was higher than the average ...
To determine what will happen to the class average once John's score is included, we need to calculate the new average.
To do this, we need to consider the total number of scores and the total sum of scores before John's score is included.
Since there is no information given about the total number of scores or the sum of scores before John's score, we cannot accurately calculate the new average.
Therefore, the correct answer is B. There is not enough information.
To determine what will happen to the class average once John's score is included, we need to calculate the new average.
Currently, the class average is 79%. This means that all the students combined have an average score of 79%.
To find the new average after including John's score, we need to add John's score to the total sum of all the other scores and then divide that sum by the total number of students.
Let's assume there are N students in the class, excluding John. The total sum of all the other scores would be (N * 79), since each student's score is assumed to be 79%.
Now, if we include John's score of 86%, the total sum of all the scores would be ((N * 79) + 86).
Since we know that John scored 86%, we can say that N * 79 represents the total sum of scores for all the other students.
So, we can rewrite the total sum of all the scores as ((N * 79) + John's score).
Next, we divide this sum by the total number of students, which is N + 1 (including John), to find the new average.
Therefore, the expression for the new average can be written as: ((N * 79) + 86) / (N + 1).
Now, we cannot determine the specific value of the new average without knowing the number of students in the class (N). Therefore, the answer is B. There is not enough information to determine what will happen to the class average.