How many committees of 2 people are possible from a group of 11?
165
22**
13
55
22 is not correct
There are 11 choices for the 1st person
There are therefore 10 choices for the 2nd person
But the order does not matter, so divide by 2
11C2 = (11*10)/(1*2) = 55
Time to review permutations and combionations
Well, let me put on my math skills and see what I can come up with. So, we have a group of 11 people, and we want to form committees of 2. To figure out the number of possible committees, we can use the combination formula, which is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items you want to select.
So, in this case, we have 11 people and we want to select 2. Plugging in the numbers, we get:
11C2 = 11! / (2!(11-2)!) = 55.
So it looks like the right answer here is 55. But hey, don't take my word for it. Math has been known to have a sense of humor too, so it might be pulling a prank on us. But for now, let's go with 55 and hope it's not playing a joke on us!
To find the number of committees of 2 people from a group of 11, you can use the combination formula.
The number of ways to choose 2 people from a group of 11 can be calculated using the combination formula:
C(n, r) = n! / (r!(n-r)!)
In this case, n = 11 (the number of people in the group) and r = 2 (the number of people we want to choose).
Plugging these values into the formula, we have:
C(11, 2) = 11! / (2!(11-2)!)
= 11! / (2!9!)
Calculating the factorial terms:
11! = 11 * 10 * 9!
2! = 2 * 1
Simplifying the expression:
C(11, 2) = (11 * 10 * 9!) / (2 * 1 * 9!)
= (11 * 10) / (2 * 1)
= 110 / 2
= 55
Therefore, the number of committees of 2 people possible from a group of 11 is 55.
To find the number of committees of 2 people possible from a group of 11, we can use the combination formula.
The combination formula is given by:
C(n, r) = n! / (r!(n-r)!)
Where n is the total number of items, and r is the number of items chosen.
In this case, we want to find the number of committees of 2 people from a group of 11, so n = 11 and r = 2.
Using the formula, we can calculate:
C(11, 2) = 11! / (2!(11-2)!) = 11! / (2!9!)
Now, let's calculate the factorial terms:
11! = 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 39,916,800
2! = 2 x 1 = 2
9! = 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 362,880
Now, substitute the factorial terms back into the combination formula:
C(11, 2) = 39,916,800 / (2 x 362,880)
Simplifying:
C(11, 2) = 39,916,800 / 725,760
C(11, 2) ≈ 55
Therefore, there are 55 possible committees of 2 people that can be formed from a group of 11.