Math

An object is projected directly upward from the ground. After t seconds it’s distance in feet above the ground is s=144t-16t^2

How long does it take the object to reach its maximum height?
What is the maximum height the object reaches? When does it hit the ground?

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  1. as with all quadratics ax^2+bx+c, the vertex (max or min) is at -b/2a
    The max height is c - b^2/4a
    since s = 16t(9-t) the roots (where s=0, that is, the object is on the ground) are at t=0, 9

    don't forget your general knowledge about parabolas when you are confronted by the equation ...

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    oobleck

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