in a class of 33 students, 18 play football, 12 play basketball and 7 play both games. How many students play none of the the two games. a). 3 b). 8 c). 10 d). 5?
33-(18+12-7) = ?
To find the number of students who play none of the two games, we need to subtract the number of students who play football or basketball (including those who play both) from the total number of students in the class.
Total number of students = 33
Number of students who play football = 18
Number of students who play basketball = 12
Number of students who play both games = 7
To find the number of students who play none of the two games, we can use the principle of inclusion-exclusion.
Number of students who play none of the two games = Total number of students - (Number of students who play football + Number of students who play basketball - Number of students who play both games)
Number of students who play none of the two games = 33 - (18 + 12 - 7)
Number of students who play none of the two games = 33 - (30 - 7)
Number of students who play none of the two games = 33 - 23
Number of students who play none of the two games = 10
Therefore, the answer is c) 10.
To find out how many students play none of the two games, we need to subtract the number of students who play both games from the total number of students.
Given that there are 33 students in total, and 7 students play both football and basketball, we can calculate the number of students who play none of the two games by subtracting these two quantities:
33 - 7 = 26
So, there are 26 students who play none of the two games.
Therefore, the correct answer is d). 5.