The mean of a data set is 7.8, the made is 6.6, and the median is 6.8. What is the least possible number of data values in the set?
A 3 data values
B 4 data values
C 5 data values
D 6 data values
I'm not really sure how I'm supposed to figure this out but i think its A because its the smallest.
HERE ARE ALL THE ANSWERS
REEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
1.D
2.B
3.A
4.D
5.A
6.D
7.B
8.A
9.B
10.A
Sorry but prank time dudes but still those are 100% the answers for
Lesson 5: Measures of Central Tendency and Dispersion CE 2015
Algebra 1 Foundations B Unit 5: Radical Expressions and Data Analysis
If the mode is 6.6, then it occurs more times than any other value (let's assume just twice)
If there are an odd number of values, and the median is 6.8, then that means that as many values are higher than the median, as there are values less than the median. Since we know that 6.6 occurs twice, that means our data set now stands at
6.6, 6.6, 6.8 x x
On the other hand, the median can also be the average of the two middle values, if there are an even number of values, so our data set could be
6.6, 6.6, 7.0, x
But, the mean is 7.8, so we need an outlier to raise the average value.
6.6+6.6+7.0+x = 4*7.8
x = 11
So, our data set could be 6.6, 6.6, 7.0, 11.0
So, I pick B
Indeed, A Low Life Team is right ^^
Indeed you are right..!!!
Well, I can certainly understand why you might think that! After all, "A" does stand for "awesome," and who doesn't want the smallest number of data values? But in this case, the answer is actually "C," which stands for "clownishly correct." Let me explain why.
The median is the middle value when the data is arranged in order, and in this case, the median is 6.8. Since the mean is 7.8, we know that there must be some larger values in the data set. If we only had 3 data values, the mean and median would be the same. So to have a mean larger than the median, we need at least 5 data values.
So, the least possible number of data values in the set is "C" - 5 data values. Keep up the great work, and don't underestimate the power of clown logic!
To determine the least possible number of data values in the set, we need to consider the relationship between the mean, median, and mode of a data set.
The mode refers to the value(s) that occur most frequently in the data set. In this case, it is not mentioned, so we can ignore it.
The median is the middle value of the data set when it is arranged in ascending or descending order. In this case, the median is given as 6.8.
The mean is the average of all the values in the data set. In this case, the mean is given as 7.8.
If we want to minimize the number of data values in the set, we can assume that the given mean and median are the actual values themselves, rather than being rounded. Therefore, we can represent the data set as follows: 6.8, 7.8, 7.8, 7.8, 7.8, .....
As we can see, this set has a mean of 7.8, a median of 6.8, and it can be continued indefinitely using the value 7.8 without affecting these measures.
Hence, the least possible number of data values in the set is 6.
Therefore, the correct answer is option D) 6 data values.