How many joules of heat energy are required to raise the temperature of 20 grams of water by 50°C?
To find out how many joules of heat energy are required to raise the temperature of water, we can use the specific heat capacity of water.
The specific heat capacity of water is 4.18 joules per gram per degree Celsius (J/g°C). This means that it takes 4.18 joules of heat energy to raise the temperature of 1 gram of water by 1 degree Celsius.
In this case, we need to raise the temperature of 20 grams of water by 50°C. So, we can calculate the heat energy required using the formula:
Heat energy = mass × specific heat capacity × temperature change
Plugging in the values, we get:
Heat energy = 20 grams × 4.18 J/g°C × 50°C
Calculating this results in:
Heat energy = 4180 joules
Therefore, it takes 4180 joules of heat energy to raise the temperature of 20 grams of water by 50°C.
To calculate the amount of heat energy required to raise the temperature of an object, you can use the formula:
Q = m * c * ∆T
Where:
Q = heat energy (in joules)
m = mass of the object (in grams)
c = specific heat capacity of the substance (in J/g°C)
∆T = change in temperature (in °C)
In this case, you have:
m = 20 grams
c (for water) = 4.18 J/g°C
∆T = 50°C
Now, let's substitute these values into the formula:
Q = 20 grams * 4.18 J/g°C * 50°C
Calculating this equation gives us:
Q = 4180 joules
Therefore, 4180 joules of heat energy are required to raise the temperature of 20 grams of water by 50°C.
q = m*c*delta T
Joules = mass H2O x specific heat H2O x 50 = ?