0.050 mole of gas was collected in the lab at a temperature of 22.0 degrees celsius and a pressure of 0.987 atm. what volume will the gas occupy under these conditions

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  1. at stp, .05 mole occupies .05 * 22.4 = 1.12 L
    since PV=kT, PV/T = k, a constant
    So, you want V such that
    0.987V/(22.0+273.15) = 1*1.12/273.15
    V = 1.226 L

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