A locker combination has two nonzero digits, and the digits can be repeated. The first number is 3. What is the probability that the second number is 3?
nevermind i figured it out it was B) 1/9
the possibilities are
A) 1/27
B) 1/9
C) 1/8
D) 8/9
we're trying to find the probability that the second number of the locker combination is 3
What are the possibilities and what number are we looking to find the probability of?
To find the probability that the second number in the locker combination is 3, we need to determine the total number of possible combinations first.
Since the first number is fixed at 3, we have nine choices for the second number (0, 1, 2, 3, 4, 5, 6, 7, 8, and 9). Therefore, the total number of possible combinations is 9.
Next, we need to determine the number of favorable outcomes, i.e., the number of combinations where the second number is 3. Since the first number is already 3, we have one favorable outcome.
Now we can calculate the probability by dividing the number of favorable outcomes by the total number of possible combinations:
Probability = Number of favorable outcomes / Total number of possible combinations
Probability = 1 / 9 = 1/9 ≈ 0.1111 (rounded to four decimal places)
Therefore, the probability that the second number in the locker combination is 3 is approximately 0.1111 or 1/9.
Remember that the probability assumes that the digits can be repeated, and there are two non-zero digits in total.