A locker combination has three nonzero digits, and digits cannot be repeated. The first two digits are 9 and 8. What is the probability that the third digit is 7?
only 7 digits left to choose from
and the 7 is one of them ..... so .....
Whats the answer if its not 1/8? ;-;
The answer choices are:
A) 1/9
B) 1/3
C) 1/8
D) 1/7
aaaaaaaaaaaa
its imposible
is 1/7 i think
Re
Yes, you are correct! There are seven remaining digits to choose from, and only one of them is a 7. Therefore, the probability that the third digit is 7 is 1/7. So the answer is option D) 1/7.
To find the probability, we need to determine the total number of possible combinations and the number of combinations where the third digit is 7.
Since the first two digits are fixed (9 and 8), we only need to consider the options for the third digit.
Since the digits cannot be repeated, there are 8 possible choices for the third digit (0, 1, 2, 3, 4, 5, 6, and 7). However, we specifically need the third digit to be 7. Therefore, there is only 1 favorable outcome.
Hence, the probability that the third digit is 7 is 1 out of 8.
Mathematically, the probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 1 / 8
Probability = 0.125
Therefore, the probability that the third digit is 7 is 0.125 or 12.5%.