# algebra

Solve the system of equations algebraically. Show all of your steps.

y=x^2+2x
**y=x^2+2x
(2/2)^2=1

y=3x+20
**y=3x+20
(3/2)^2=2.25

am i right or wrong, if im wrong could someone show me the steps

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1. the system of equations is
y=x^2+2x
y=3x+20
You want to find a value of x that makes both equations true. So, since the expressions must be equal,
x^2 + 2x = 3x + 20
x^2 - x - 20 = 0
(x-5)(x+4) = 0
x = 5 or -4

check:
5^2 + 2*5 = 35
3*5 + 20 = 35

(-4)^2 + 2(-4) = 16-8 = 8
3(-4)+20 = -12+20 = 8

So, yes, both values are solutions to both equations

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oobleck

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