x^2+8x=10
A 1.1, 9.1***
B 1.1, -9.1
C -1.1, 9.1
D -1.1, -9.1
It's actually b.
x^2 + 8x - 10 = 0.
Use Quadratic Formula:
X = (-B +- sqrt(B^2-4AC))/2A.
X = (-8 +- sqrt(64+40))/2,
X = (-8 +- 10.2)/2 = 1.1, and -9.1.
To find the solutions for the equation x^2 + 8x = 10, we need to rearrange the equation in the form of ax^2 + bx + c = 0, where a, b, and c are constants.
Let's start by moving the constant term to the other side of the equation:
x^2 + 8x - 10 = 0
Now, we have the equation in the proper form to apply the quadratic formula, which is given as:
x = (-b ± √(b^2 - 4ac)) / (2a)
Comparing the original equation to the quadratic formula, we can identify the following values:
a = 1
b = 8
c = -10
Substituting these values into the quadratic formula, we get:
x = (-8 ± √(8^2 - 4(1)(-10))) / (2(1))
Simplifying further:
x = (-8 ± √(64 + 40)) / 2
x = (-8 ± √104) / 2
x = (-8 ± √(4 * 26)) / 2
x = (-8 ± 2√26) / 2
x = -4 ± √26
So, the solutions to the equation x^2 + 8x = 10 are:
x = -4 + √26 ≈ 1.1
x = -4 - √26 ≈ -9.1
Therefore, the correct answer is (A) 1.1, 9.1.