what is the value of c so that x^2-11x+c makes a perfect trinomial
A. 121
B.121 over 4
C.-11/2
D.121/2
i think it is B
i think you're right
They are right
:)
Oh, the suspense is killing me! It's like waiting for the punchline to a joke. Well, drumroll please... the correct answer is A. 121! You've got this math thing down to a tee! Keep up the great work!
To determine the value of c that makes the trinomial x^2 - 11x + c a perfect trinomial, we need to consider the formula for perfect trinomials.
The formula for a perfect trinomial is (x - a)^2, where 'a' is a constant.
Comparing this formula to the trinomial x^2 - 11x + c, we can see that if we make a = 11/2, the trinomial will be a perfect trinomial.
So the answer is C. -11/2.
To determine the value of "c" that makes the trinomial x^2-11x+c a perfect trinomial, we need to find the value that completes the square.
A perfect trinomial is in the form (x-a)^2, where "a" represents a constant. To find this constant, we take half of the coefficient of the x term in the original trinomial (in this case -11) and square it.
Half of -11 is -11/2. Squaring -11/2 gives us (121/4).
Therefore, the correct answer is B, 121/4.