A bag has 2 red marbles, 1 blue marble and 4 gold marbles. What is the probability of drawing two gold marbles, if the first marble is replaced after it is drawn?
C. 4/7
D. 7/13
( I didn't add A or B `cause i knew those were wrong)
since you are replacing the marble the two events are independent, so multiply the two probs.
What is the prob(drawing a red) ?
so prob(2 reds - with replacement) = (4/7)(4/7) = 16/49
(perhaps one of the choices you rejected)
To find the probability of drawing two gold marbles with replacement, we need to consider the total number of marbles and the number of gold marbles.
The total number of marbles in the bag is:
2 red marbles + 1 blue marble + 4 gold marbles = 7 marbles
The number of gold marbles is 4.
When we draw the first marble and replace it, the total number of marbles in the bag remains the same. So, for each draw, the probability of drawing a gold marble is 4/7.
Since we want to find the probability of drawing two gold marbles in a row, we need to calculate the probability of drawing a gold marble for the first draw and then multiply it by the probability of drawing a gold marble for the second draw.
Probability of drawing a gold marble in the first draw = 4/7
Probability of drawing a gold marble in the second draw (with replacement) = 4/7
To calculate the probability of both events happening, we multiply the probabilities:
4/7 * 4/7 = 16/49
Therefore, the correct answer is not listed among the options. The probability of drawing two gold marbles, with replacement, is 16/49.