A locker combination has three nonzero digits, and digits cannot be repeated. If the first digit is 3, what is the probability that the next digit is odd?
A.4/9
B.1/5
C.1/2
D.5/9
The three is used up as the first digit, so there are the numbers 1,5,7 and 9 left to be the next digit. There are 4 such outcomes that can be the second digit. The total number of digits that can be used for each slot is 8. So 4 out of 8 digits : )
probability is just figuring what fraction of all possible choices gives you success. Ms Pi said
So 4 out of 8 digits
that means your probability is 4/8 = 1/2
I hope this is getting clearer now ...
can i just get the answer
can't you guys just join to brainly app is better
This really didn't help me out that much....
but thanks for trying
kare she just gave you the answer by saying that 4/8 i= 1/2 and 1/2 is one of the answers.
To find the probability that the next digit is odd, we need to first determine the total number of possible combinations and then count the number of favorable outcomes.
Given that the first digit is 3, we have only two digits left to fill the remaining two spots. Since the digits cannot be repeated and we have three nonzero digits to choose from (1, 2, 4), we have a total of 3 choices for the second digit and 2 choices for the third digit.
Therefore, the total number of possible combinations is 3 * 2 = 6.
Out of these 6 possible combinations, there are three combinations where the next digit is odd: 31, 34, and 32.
So the number of favorable outcomes is 3.
The probability of an event occurring is given by the formula: Probability = (Number of Favorable Outcomes) / (Total Number of Possible Outcomes).
Therefore, the probability that the next digit is odd is 3 / 6 = 1 / 2.
Hence, the correct answer is C. 1/2.