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A baseball is thrown up in the air from a height of 3 feet with an initial velocity of 23 feet per second. When does the baseball hit the ground?

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  1. height = -16t^2 + 23t + 3

    you want height = 0
    so solve the quadratic
    -16t^2 + 23t + 3 = 0
    or
    16t^2 - 23t - 3 = 0
    Hint: it does not factor, so use the quadratic formula, reject the negative answer

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    Reiny
  2. V = Vo + g*Tr = 0.
    23 + (-32)Tr = 0,
    Tr = 0.72 s. = Rise time.

    h = ho + Vo*Tr + 0.5g*Tr^2 = 3 + 23*0.72 + (-16)*0.72^2 = 11.3 Ft. above gnd.

    h = 0.5g*Tf^2 = 11.3.
    16Tf^2 = 11.3,
    Tf = 0.84 s. = Fall time.

    Tr + Tf = 0.72 + 0.84 = --------s. = Time to reach gnd.

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