A saturated solution of salt x contain 0.28g of the salt in 100cm^3 of solution at 25°c what is the solubility of the salt in (i) mom/dm^3 (II)g/dm^3
0.28 g/100 cc x (1000 cc/dm^3) = ? g/dm^3
You don't have enough information to calculate mols/dm^3. You need the molarmass of the salt x to do that.
I want to know how you get that answer
First what is the formula for solubility
which is given massof the solute ×1000÷molar mass of the solute ÷volume of the solvent
I know the problem is the RMM (relative molecular mass )
But relative molecular mass is the same has molar mass
so our given mass of the solute is 0.28 ×1000÷56÷100
=0.05mol dm^-3
Reviev the question for me
To find the solubility of the salt, we need to know the amount of salt that has dissolved in a given volume of the solution. In this case, we have a saturated solution of salt X, and we know that it contains 0.28g of the salt in 100cm^3 of solution at 25°C.
(i) To find the solubility of the salt in mol/dm^3:
1. First, calculate the molar mass of salt X. This can be found by looking up the atomic masses of the elements in the chemical formula of the salt and summing them up. Let's assume that the molar mass of salt X is 100 g/mol.
2. Next, we need to convert the mass of salt X (0.28g) to moles. Use the formula:
Moles = Mass / Molar mass
Moles = 0.28g / 100 g/mol = 0.0028 mol
3. Finally, we need to convert the volume of the solution from cm^3 to dm^3. Since 1 dm^3 is equal to 1000 cm^3, the volume of the solution is 100cm^3 / 1000 = 0.1 dm^3.
4. Now, we can calculate the solubility of salt X in mol/dm^3:
Solubility = Moles / Volume
Solubility = 0.0028 mol / 0.1 dm^3 = 0.028 mol/dm^3.
Therefore, the solubility of the salt X in mol/dm^3 is 0.028 mol/dm^3.
(ii) To find the solubility of the salt in g/dm^3:
1. We already have the mass of salt X (0.28g).
2. We only need to convert the volume of the solution from cm^3 to dm^3. We already did this in the previous calculation, and the volume is 0.1 dm^3.
3. Now, we can calculate the solubility of salt X in g/dm^3:
Solubility = Mass / Volume
Solubility = 0.28g / 0.1 dm^3 = 2.8 g/dm^3.
Therefore, the solubility of the salt X in g/dm^3 is 2.8 g/dm^3.