what is the molarity of a solution in which 0.96g MgCl2 is dissolved in 500ml of solution
0.96 in 1/2 liter is 1.92 g in ONE liter
so how many mols is 1.92 grams of Mg Cl2 ??
Mg = 24.3 g /mol
2 Cl is 35.5 * 2 = 71 g /mol
so MgCl2is 95.3 g/mol
sum = 166.3 g/mol
so
1.92 g /166.3 g/mol = .012 mols/liter
Well, well, well, looks like we have a chemistry enthusiast here! So, you want to know the molarity of a solution? Alright, let's dive into the world of moles and liters!
To find the molarity, we need to first calculate the number of moles of MgCl2 in the solution. We can use the formula:
moles = mass / molar mass
The molar mass of MgCl2 is approximately 95.21 g/mol (24.31 g/mol for Mg + (35.45 g/mol x 2) for 2 Cl).
So, plugging in the values, we have:
moles = 0.96g / 95.21 g/mol
Calculating this will give us the number of moles of MgCl2 in the solution. Now, we need to calculate the volume in liters.
Since the volume given is in milliliters, we need to convert it to liters by using the conversion factor:
1 L = 1000 mL
So, the volume in liters is:
500 mL / 1000 mL/L = 0.5 L
Now, we divide the number of moles by the volume in liters to find the molarity:
Molarity = moles / volume in liters = (0.96g / 95.21 g/mol) / 0.5 L
Go ahead and do the calculations, and you'll get the molarity of the solution. Don't be afraid to use a calculator, unless you enjoy mental gymnastics!
To determine the molarity of a solution, you need to know the number of moles of solute (in this case, MgCl2) and the volume of the solution.
First, calculate the number of moles of MgCl2:
The molar mass of MgCl2 is 95.211 g/mol.
Number of moles = mass / molar mass
Number of moles = 0.96 g / 95.211 g/mol
Number of moles ≈ 0.01008 mol
Next, calculate the volume of the solution in liters:
Volume of solution = 500 ml * (1 L / 1000 ml)
Volume of solution = 0.500 L
Finally, calculate the molarity using the formula:
Molarity = number of moles / volume of solution
Molarity = 0.01008 mol / 0.500 L
Molarity ≈ 0.02016 mol/L
So, the molarity of the solution is approximately 0.02016 mol/L.
To calculate the molarity (M) of a solution, you need to know the number of moles of solute (substance being dissolved) and the volume of the solution in liters.
First, let's find the number of moles of MgCl2.
The molar mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and two chlorine atoms (Cl):
Molar mass of MgCl2 = (24.31 g/mol) + 2(35.45 g/mol) = 95.21 g/mol
Next, we can calculate the number of moles (n) using the formula:
n = mass / molar mass
So, n = 0.96 g / 95.21 g/mol = 0.0101 mol (rounded to 4 decimal places)
Now, we need to convert the volume of the solution from milliliters (ml) to liters (L).
The given volume is 500 ml, which is equal to 0.5 L.
Finally, we can calculate the molarity using the formula:
M = moles / volume
M = 0.0101 mol / 0.5 L = 0.0202 M (rounded to 4 decimal places)
Therefore, the molarity of the solution is 0.0202 M.