If a force of 40N stretches a wire from 20m to 20.02m, what is the amount of force required to stretch the same material from 20m to 20.07m?

what is 7/2 * 40N?

0.07/0.02 * 40 = 7/2 * 40 =

To find the amount of force required to stretch the wire from 20m to 20.07m, we can use Hooke's Law. Hooke's law states that the force required to stretch or compress a spring is directly proportional to the displacement or change in length.

First, let's find the change in length of the wire:
Change in length = Final length - Initial length
Change in length = 20.07m - 20m
Change in length = 0.07m

Now, let's use Hooke's Law to find the amount of force required:
Force = (Spring constant) * (Change in length)

Hooke's Law formula can be rearranged to solve for spring constant:
Force = (k) * (Change in length)
k = Force / (Change in length)

Given that the force required to stretch the wire from 20m to 20.02m is 40N, and the change in length is 0.02m, we can calculate the spring constant (k):
k = 40N / 0.02m
k = 2000 N/m

Now that we have the spring constant, let's find the force required to stretch the wire from 20m to 20.07m:
Force = k * Change in length
Force = 2000 N/m * 0.07m
Force = 140 N

Therefore, the amount of force required to stretch the same material from 20m to 20.07m is 140N.