How is the work done to hoist the counterweight related to the potential energy of the counterweight at its specified height?

should be the same ... minus any frictional losses

To understand the relationship between the work done to hoist the counterweight and its potential energy at a specific height, let's first define a few concepts.

1. Work: In physics, work is defined as the transfer of energy that occurs when a force is applied to an object, causing it to move in the direction of the force. Mathematically, work (W) can be calculated as the product of the force applied (F) and the displacement (d) of the object in the direction of the force: W = F * d * cos(theta), where theta is the angle between the force and the displacement vectors.

2. Potential Energy: Potential energy is the energy possessed by an object due to its position or state. In the case of the counterweight, we are specifically concerned with gravitational potential energy. The gravitational potential energy (PE) of an object is determined by its mass (m), acceleration due to gravity (g), and height (h) above a reference level. Mathematically, PE = m * g * h.

Now let's consider how the work done to hoist the counterweight is related to its potential energy at a specified height:

When the counterweight is hoisted to a specific height, work is done against the force of gravity to raise it. The work done to lift the counterweight is equal to the change in its potential energy.

The work done (W) to hoist the counterweight is given by the equation W = F * d * cos(theta). In this case, the force applied is the force required to overcome the gravitational force on the counterweight (F = m * g, where m is the mass of the counterweight and g is the acceleration due to gravity). The displacement (d) is the height (h) to which the counterweight is lifted. The angle (theta) between the force and displacement vectors is 0 degrees since the force and the displacement are in the same direction.

Substituting these values into the equation, we get W = (m * g) * h * cos(0) = m * g * h.

This equation indicates that the work done is equal to the change in the potential energy of the counterweight at a specific height. Therefore, the work done to hoist the counterweight is directly related to the potential energy of the counterweight at that height, as both quantities are proportional to the mass of the counterweight, the acceleration due to gravity, and the height reached.