How many moles of oxygen will be consumed when 5 moles of pentane are combusted?
n=m/FM
=360/16
=22.5 moles
google pentane combustion
the units in the reaction equation are moles
To determine the number of moles of oxygen consumed in the combustion of pentane, we need to determine the balanced chemical equation for the combustion reaction.
The chemical formula for pentane is C5H12, and its combustion equation can be written as:
C5H12 + x O2 → y CO2 + z H2O
Here, x represents the number of moles of oxygen required for complete combustion, y represents the number of moles of carbon dioxide produced, and z represents the number of moles of water produced.
To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
Since pentane has 5 carbon atoms, we need 5 moles of carbon dioxide.
Since pentane has 12 hydrogen atoms, we need 6 moles of water.
This means that for every 1 mole of pentane, we need 5 moles of oxygen.
Therefore, if we have 5 moles of pentane, we will need 5 moles of oxygen.
So, the answer is 5 moles of oxygen will be consumed when 5 moles of pentane are combusted.