Baking soda is sodium bicarbonate (NaHCO3). When you heat baking soda, it breaks down into sodium carbonate powder (Na2CO3), water vapor, and carbon dioxide. The enthalpy of this reaction is 129 kJ. Write a correct thermochemical equation for this reaction, explain how you came up with this equation, and explain what it tells you about the reaction.
please help me with this
The way you have written this post I can't tell if that is 120 kJ/mol or 120 kJ for the reaction as written. I have shown it as 120 kJ/reaction. If it is120 kJ/mol then you would show 240 kJ/reaction.
2NaHCO3 ==> Na2CO3 + CO2 + H2O dH = +120 kJ
no it is just 129 kj
It must be one or the other.
The correct thermochemical equation for the reaction of heating baking soda can be written as:
2 NaHCO3(s) → Na2CO3(s) + H2O(g) + CO2(g)
To come up with this equation, we need to consider the balanced equation for the reaction and include the physical states of the substances involved.
First, we observe that there are two sodium bicarbonate molecules (2 NaHCO3) and that leads us to include the coefficient '2' in front of NaHCO3 in the equation. Next, the products of the reaction are sodium carbonate (Na2CO3), water vapor (H2O), and carbon dioxide (CO2). Therefore, we include the appropriate physical states, ‘(s)’ for solid and ‘(g)’ for gas.
The reaction tells us that when baking soda is heated, it undergoes decomposition. It breaks down into sodium carbonate powder, water vapor, and carbon dioxide. The positive enthalpy change of 129 kJ indicates that the reaction is endothermic, meaning it absorbs heat from the surroundings. This energy is required to break the bonds within the baking soda molecules and form the new products.