A machine with v.r of 5 requires 1000No of work to raise a load of 500N through a vertical distance of 1.5. ( a ) find the efficiency of the machine. (B) calculate it's mechanical advantage
a. eff. = Wo/Wi = (500*1.5)/1000 =
b. Vr = de/dl = 5,
de/1.5 = 5,
de = 7.5 m. = distance moved by the Effort(E).
E * de = 1000 J.
E * 7.5 = 1000,
E = 133.3 N. = Effort.
M.A. = L/E = 500/133.3 =
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To find the efficiency of the machine, you need to know the work input and the work output. The formula for efficiency is:
Efficiency = (Work output / Work input) x 100%
In this case, the work input is given as 1000 No (Newton) of work. The work output can be calculated by multiplying the load lifted (500N) by the vertical distance covered (1.5m). Thus, the work output is:
Work output = Load lifted x Vertical distance covered
= 500N x 1.5m
= 750 Nm
Now we can calculate the efficiency using the formula mentioned earlier:
Efficiency = (Work output / Work input) x 100%
= (750 Nm / 1000 No) x 100%
= 75%
Therefore, the efficiency of the machine is 75%.
To calculate the mechanical advantage of a machine, we need to know the load lifted and the effort applied. The formula for mechanical advantage is:
Mechanical Advantage = Load lifted / Effort applied
In this case, the load lifted is given as 500N. The effort applied is not provided directly, but we can calculate it by dividing the work input by the vertical distance covered:
Effort applied = Work input / Vertical distance covered
= 1000 No / 1.5m
= 666.67 No (rounded to three decimal places)
Now we can calculate the mechanical advantage using the formula mentioned earlier:
Mechanical Advantage = Load lifted / Effort applied
= 500N / 666.67 No
= 0.75 (rounded to two decimal places)
Therefore, the mechanical advantage of the machine is 0.75.