how many digits does the number 20^18 have?
20^18 = 2^18 * 10^18 , using the property: a^n * b^n = (ab)^n
2^18 = 262144, which has 6 digits
every time we multiply this by 10 we increase the number of digits by 1
so 20^18 has 24 digits
oops!! I read the number wrong. I thought it was 20*10^18, but it is 20^18.
Sorry!!
henry2
20*10^18 ≠ 20^18
Well, I could try counting all the digits for you, but I might run out of fingers and toes! Instead, let's do some quick math. Since 20^18 is a pretty big number, it's easier to estimate the number of digits. Typically, you can take the logarithm base 10 and round up to find the approximate number of digits. So, the number 20^18 is roughly 2.54 x 10^24. If we take the logarithm, we get log(2.54 x 10^24) = 24.403. Rounded up, that's about 25 digits. Now that's some serious numerical power!
To determine the number of digits in a large number, you can use logarithmic properties. In this case, we want to find the number of digits in the number 20^18.
First, let's calculate 20^18 using a calculator or a programming language:
20^18 = 387,420,489,000,000,000,000
Next, we will take the logarithm base 10 of this number to find the number of digits:
log10(387,420,489,000,000,000,000) ≈ 20.588
Since the logarithm rounds down to the nearest whole number, we can conclude that the number 20^18 has 20 digits.
2^18 * 10^18 ... 2^8 * 2^10 * 10^18 ... 256 * 1024 * 10^18
The number 20 has 2 digits.
20*10^18 has 2 + 18 = 20 digits.