a Quadrilateral ABCD, AB=10m, angle ABD=40 degrees and angle ADB=80 degrees.
Sketch the diagram and determine the distance from B to D
Ok, I drew the diagram.
If you are following the convention of listing points in sequence, then quadrilateral ABCD
doesn't enter the problem, and we are just talking about triangle ABC
You are given 2 of its angles, so you can find the third.
by the sine law:
BC/sinA = 10/sin80