in the circuit below find the volts at V4
4 is grounded
R1 is 15 volts
R2 is 12 volts
R3 is 10 volts
www.ibiblio.org/kuphaldt/electricCircuits/DC/00082.png
my answer is
15v+12v+10v =37v
if V1=37v,
then v2=37v-15v = 22v,
then v3=37v-15v-12v = 10v
then v4= 37v-15-12v-10v =0v
At V4 the voltage is at 0v
is my answer correct???
No circuit shown, however, if V4 is at ground potential, it is 0 volts.
it's in the link above
yes, zero.
To find the voltage at V4 in the circuit, you need to take into account the voltage drops across each resistor.
First, let's assign a reference point for ground, which is connected to point V4. This means that V4 is at 0 volts.
To determine the voltage at V2, you subtract the voltage drop across R1 (15V) from the applied voltage (V1). So:
V2 = V1 - VR1
V2 = 37V - 15V
V2 = 22V
Next, to find the voltage at V3, you subtract the voltage drop across both R1 and R2 (15V + 12V) from the applied voltage (V1):
V3 = V1 - VR1 - VR2
V3 = 37V - 15V - 12V
V3 = 10V
Finally, to find the voltage at V4, you subtract the voltage drops across all three resistors (R1, R2, and R3) from the applied voltage (V1):
V4 = V1 - VR1 - VR2 - VR3
V4 = 37V - 15V - 12V - 10V
V4 = 0V
Therefore, your answer of V4 being at 0 volts is correct.