a 40m deep well with radius 3.5m is dug and the earth taken out is evenly spred to form aplat form of dimenshins 28m by 22m find the heght of theplat form?
56
thickness = volume/area
so,
thickness = (π*3.5^2*40)/(28*22) = 2.5m
Vw = pi*r^2*d = 3.14 * 3.5^2 * 40 = 1539 m^3. = Vol. of well.
Vp = L*W*h = 1539.
28 * 22 * h = 1539,
h = 2.5 m.
To find the height of the platform formed by spreading the earth from the well, we can use the principle of conservation of volume.
First, let's calculate the volume of the earth removed from the well. The well can be approximated as a cylinder, so the volume of the earth removed is given by:
Volume of well = πr^2h
= π(3.5^2)(40)
= 4900π cubic meters
Next, let's calculate the area of the platform formed by spreading the earth. The platform is rectangular, so the area is given by:
Area of platform = length × width
= 28 × 22
= 616 square meters
Now, we can find the height of the platform by dividing the volume of the earth removed by the area of the platform:
Height of platform = Volume of well / Area of platform
= (4900π) / 616
≈ 25.568 meters
Therefore, the height of the platform formed by spreading the earth from the well is approximately 25.568 meters.