Solve the inequality. Then graph the solution on a number line.
-16 is less than or equal to 2x = 8<10
I'm going to assume your problem was meant to be this:
-16 ≤ 2x + 8 < 10
If so, start by subtracting 8 on all sides:
-16 - 8 ≤ 2x + 8 - 8 < 10 - 8
-24 ≤ 2x < 2
Now divide everything by 2 to get x by itself:
-24/2 ≤ 2x/2 < 2/2
-12 ≤ x < 1
Graph on a number line.
I hope this will help.
To graph the solution on a number line for the inequality -16 ≤ 2x + 8 < 10, we first need to solve it.
Start by subtracting 8 on all sides:
-16 - 8 ≤ 2x + 8 - 8 < 10 - 8
-24 ≤ 2x < 2
Next, divide all sides by 2 to isolate x:
-24/2 ≤ 2x/2 < 2/2
-12 ≤ x < 1
Now, let's graph this solution on a number line.
Start by drawing a horizontal line and marking a point at -12:
-----o--------------------
Then mark a point at 1:
-----o-------------o--------
We can notice that the inequality is "less than" and "less than or equal to". This means we need to fill in the dots on the number line.
Since -12 is included in the solution (because of the "less than or equal to" sign), we fill in the dot at -12 with a solid circle:
◯--------------------------
Since 1 is not included in the solution (because of the "less than" sign), we fill in the dot at 1 with an open circle:
◯---------------------○----
Finally, draw a line between the two points to indicate that all values between -12 and 1 are part of the solution:
◯------------------------○
This graph represents the solution to the given inequality. All numbers on the line between -12 and 1, including -12 but not including 1, satisfy the original inequality.