Two gases A & B haue densities of 0.09 g/cm^3 and 0.16 g/cm^3 respectively.

If they diffuse under the same conditions, determine their relative rates of diffusion.

As molar mass increases density increases so

(rate A)/rate B) = sqrt(denity B/density A)
Post your work if you get stuck.

Answer

I need working of this question (two gases A,B have densities of 0.09g/cm^3 and 0.16g/cm^3 respectively .if they diffuse under the same conditions ,determine their relative rate of diffusion

To determine the relative rates of diffusion between gases A and B, we can use Graham's law of diffusion. According to Graham's law, the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.

First, let's calculate the molar masses of gases A and B. Given the densities of the gases, we need to convert them to molar masses.

The density of a gas can be calculated using the formula:

Density = Mass / Volume

Rearranging the formula, we can find the mass:

Mass = Density × Volume

Since the volume is not specified, we can assume a standard volume of 1 cm^3 for both gases.

For gas A:
Mass of A = Density of A × Volume = 0.09 g/cm^3 × 1 cm^3 = 0.09 g

For gas B:
Mass of B = Density of B × Volume = 0.16 g/cm^3 × 1 cm^3 = 0.16 g

Now, let's calculate the molar masses using the equation:

Molar Mass = Mass / Number of Moles

The number of moles for each gas will be assumed to be 1 since we are calculating the molar mass of 1 cm^3 of the gas.

For gas A:
Molar Mass of A = Mass of A / Number of Moles = 0.09 g / 1 mol = 0.09 g/mol

For gas B:
Molar Mass of B = Mass of B / Number of Moles = 0.16 g / 1 mol = 0.16 g/mol

Now that we have the molar masses of gases A and B, we can find their relative rates of diffusion.

According to Graham's law, the ratio of the rates of diffusion (R1 and R2) of two gases is given by:

R1 / R2 = √(M2 / M1)

Where M1 represents the molar mass of gas A and M2 represents the molar mass of gas B.

Calculating the relative rates of diffusion:

R1 / R2 = √(0.16 g/mol / 0.09 g/mol) = √(1.78) ≈ 1.33

Therefore, the relative rate of diffusion of gas A to gas B is approximately 1.33.