A lady drives 130km north and then 80km east, calculate the resultant displacement of the lady
A lady drives 130 km north and 80 km east
magnitude= sqrt (130^2 + 80^2)
To calculate the resultant displacement of the lady, we can treat the north and east directions as axes on a coordinate system.
First, let's calculate the distance she drives in the north direction. The lady drives 130 km north, so her displacement in the north direction is +130 km.
Next, let's calculate the distance she drives in the east direction. The lady drives 80 km east, so her displacement in the east direction is +80 km.
To find the resultant displacement, we need to use the Pythagorean theorem. The resultant displacement is the hypotenuse of a right triangle formed by the north and east directions.
Using the Pythagorean theorem, we have:
Resultant displacement^2 = (North displacement)^2 + (East displacement)^2
Let's substitute the values:
Resultant displacement^2 = (130 km)^2 + (80 km)^2
Calculating:
Resultant displacement^2 = 16900 km^2 + 6400 km^2
Resultant displacement^2 = 23300 km^2
Now, let's find the square root to get the resultant displacement:
Resultant displacement = √(23300 km^2)
Resultant displacement ≈ 152.39 km
Therefore, the resultant displacement of the lady is approximately 152.39 km.