Your school wants to take out an ad in the paper congratulating the basketball team on a successful​ season, as shown to the right. The area of the photo will be half the area of the entire ad. What is the value of​ x? The photo that is suppose to be to the right is 4 inches by 3 inches. I need both* answers and am completely stuck.

*The format answer is suppose to be: x=? or x=? written as x,x

please help me. I only have about 30 minutes to turn in my answer and can't find anything that helps.

To find the value of x, we first need to determine the area of the entire ad and the area of the photo.

The area of a rectangle can be found by multiplying its length by its width.

Given that the photo to the right is 4 inches by 3 inches, the area of the photo is:

Area of the photo = length × width = 4 inches × 3 inches = 12 square inches

Since the area of the photo is half the area of the entire ad, we can set up the following equation:

12 square inches = (1/2) × Area of the entire ad

To find the area of the entire ad, we need to undo the division by multiplying both sides of the equation by 2:

24 square inches = Area of the entire ad

Now, we have the area of the entire ad (24 square inches). However, we still need to find the dimensions of the ad to determine the value of x.

The area of the entire ad can also be calculated by multiplying its length by its width. Let's assume the ad has length L and width W.

Area of the entire ad = length × width = L × W

We know that the area of the entire ad is 24 square inches, so we can write the following equation:

24 square inches = L × W

We are also given that the area of the photo (12 square inches) is half the area of the entire ad. Therefore, we can write another equation:

12 square inches = (1/2) × L × W

Now we have a system of two equations:

1) 24 square inches = L × W
2) 12 square inches = (1/2) × L × W

To solve for the value of x, we can use either substitution or elimination method to solve the system of equations.

Let's use the elimination method to solve this system:

Multiply equation (2) by 2 to eliminate the fraction:

24 square inches = L × W
24 square inches = 2 × (1/2) × L × W

Simplifying equation (2):

24 square inches = L × W
24 square inches = L × W

Now, we have two identical equations, which means any value of L and W that satisfies one equation will also satisfy the other equation.

Therefore, the value of x can vary, and there is no unique solution for x.