Two cells, each of e.m.f. 1.5V and an internal resistance 2 Ohms are connected in parallel.
Calculate the current flowing when the cells are connected to a 1 Ohms ?
To calculate the current flowing when the two cells are connected to a 1 Ohm resistor, we first need to determine the total equivalent resistance of the circuit.
When the cells are connected in parallel, the total equivalent resistance (R_eq) can be calculated using the formula:
1/R_eq = 1/R1 + 1/R2
Where R1 and R2 are the internal resistances of the cells.
Given that R1 = R2 = 2 Ohms, we can substitute these values into the formula:
1/R_eq = 1/2 + 1/2 = 2/2 = 1
R_eq = 1 Ohm
Now we can apply Ohm's Law to calculate the current (I) flowing through the circuit:
I = V/R_eq
Where V is the total voltage across the circuit.
Since the two cells are connected in parallel, their voltages add up, so the total voltage is 1.5V + 1.5V = 3V.
Substituting the values into the formula:
I = 3V / 1 Ohm = 3 Amps
Therefore, the current flowing through the circuit when the cells are connected to a 1 Ohm resistor is 3 Amps.