Two electrons are placed one at north pole and other at South Pole of earth find force between them given diameter of earth is equal to 12800 kilometre
To find the force between two electrons placed at the North and South poles of the Earth, you can use Coulomb's Law.
Coulomb's Law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Let's denote the charge of an electron as e and the distance between the electrons as d.
1. Convert the diameter of the Earth from kilometers to meters:
Diameter of Earth = 12,800 kilometers = 12,800,000 meters.
2. Calculate the distance between the electrons:
Since the electrons are placed at the North and South poles, their distance is equal to the diameter of the Earth:
d = 12,800,000 meters.
3. Calculate the force between the electrons:
Coulomb's Law states that:
F = k * (q1 * q2) / r^2
Where:
F is the force between the charged particles,
k is the electrostatic constant (k = 9 x 10^9 N m^2/C^2),
q1 and q2 are the charges of the particles,
r is the distance between the particles.
Since the charge of an electron is -e and there are two electrons, the charges q1 and q2 are -e and -e respectively:
q1 = q2 = -e
Plugging in the values:
F = (9 x 10^9 N m^2/C^2) * (-e * -e) / (12,800,000 m)^2
4. Simplify the equation:
Since the charges q1 and q2 are both negative, their product is positive:
F = (9 x 10^9 N m^2/C^2) * (e * e) / (12,800,000 m)^2
Since e * e is equal to e^2, we can simplify further:
F = (9 x 10^9 N m^2/C^2) * (e^2) / (12,800,000 m)^2
5. Calculate the force:
Plug in the known values:
F = (9 x 10^9 N m^2/C^2) * (1.6 x 10^-19 C)^2 / (12,800,000 m)^2
Simplify further and calculate:
F ≈ 2.47 x 10^-46 Newtons
Therefore, the force between the two electrons placed at the North and South poles of the Earth is approximately 2.47 x 10^-46 Newtons.
To calculate the force between two electrons placed at the North Pole and the South Pole of the Earth, we need to use Coulomb's Law, which states that the force between two charged particles is given by:
F = (k * q1 * q2) / r^2
Where:
F is the force between the two charges,
k is the electrostatic constant (k = 9 x 10^9 Nm^2/C^2),
q1 and q2 are the charges of the two particles, and
r is the distance between the charges.
In this case, both electrons have the same charge, so q1 = q2 = e, where e is the elementary charge (approximately 1.6 x 10^-19 C).
To find the distance between the two charges, we need to consider the diameter of the Earth. Given that the diameter of the Earth is 12,800 kilometers, we can calculate the distance (r) between the North Pole and the South Pole.
r = Diameter / 2
r = 12,800 km / 2
r = 6,400 km
Now we have all the values required to calculate the force:
F = (9 x 10^9 Nm^2/C^2 * (1.6 x 10^-19 C) * (1.6 x 10^-19 C)) / (6,400,000 m)^2
Simplifying the equation:
F = (2.56 x 10^-38 Nm^2) / 40,960,000,000 m^2
F = 6.25 x 10^-49 N
Therefore, the force between the two electrons is approximately 6.25 x 10^-49 Newtons.
Ignoring the charge cloud inside the earth, as a conductor?
F=ke^2/(12.8e6)^2