A plant of brassicaceae family with tetradynamous androecium possess 20 flowers what will be the total number of microsporangia in that plant?

480

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To determine the total number of microsporangia in a plant of the Brassicaceae family with a tetradynamous androecium and 20 flowers, we need to consider the characteristics of the androecium and the number of flowers.

In the Brassicaceae family, the androecium typically consists of six stamens arranged in a tetradynamous pattern. Tetradynamous means that there are four long stamens and two short stamens.

Since each flower has an androecium, and there are 20 flowers in total, we need to calculate the number of microsporangia in each flower and then multiply it by the number of flowers.

In Brassicaceae plants, each microsporangium is located within an anther, and each stamen carries two microsporangia called pollen sacs.

Given that there are six stamens in the androecium of each Brassicaceae flower, we can calculate the total number of microsporangia in one flower as follows:

Total microsporangia in one flower = Number of stamens × Number of pollen sacs per stamen
= 6 stamens × 2 pollen sacs per stamen
= 12 microsporangia per flower

Finally, to find the total number of microsporangia in the plant with 20 flowers, we multiply the number of microsporangia per flower by the number of flowers:

Total microsporangia in the plant = Total microsporangia in one flower × Number of flowers
= 12 microsporangia per flower × 20 flowers
= 240 microsporangia

Therefore, the total number of microsporangia in the given plant with 20 flowers would be 240.