What is the percentage by mass of water of crystallization in a molecule of Na2co3.10h2o?
what is 10*18/(molmassNa2CO3.10H2)
To determine the percentage by mass of water of crystallization in a molecule of Na2CO3.10H2O, you need to calculate the mass of the water of crystallization and divide it by the total mass of the compound, then multiply by 100.
Step 1: Calculate the molar mass of Na2CO3
- Sodium (Na) has a molar mass of 22.99 g/mol, and there are 2 atoms of sodium in Na2CO3.
- Carbon (C) has a molar mass of 12.01 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol, and there are 3 atoms of oxygen in Na2CO3.
- Calculate the total molar mass of Na2CO3 by adding up the individual atomic masses: (2 * 22.99) + 12.01 + (3 * 16.00) = 105.99 g/mol.
Step 2: Calculate the mass of the water of crystallization (10H2O)
- Water (H2O) has a molar mass of (2 * 1.01) + 16.00 = 18.02 g/mol.
- Calculate the mass of 10H2O by multiplying its molar mass by the number of moles: 10 * 18.02 = 180.20 g.
Step 3: Calculate the total mass of the compound (Na2CO3.10H2O)
- The molar mass of Na2CO3 is 105.99 g/mol.
- Calculate the mass of Na2CO3.10H2O by adding the molar mass of Na2CO3 to the mass of 10H2O: 105.99 + 180.20 = 286.19 g.
Step 4: Calculate the percentage by mass of water of crystallization
- Divide the mass of 10H2O by the total mass of the compound and multiply by 100: (180.20 / 286.19) * 100 ≈ 62.99%
Therefore, the percentage by mass of water of crystallization in a molecule of Na2CO3.10H2O is approximately 62.99%.