3y-8 over 12 =y over 5

(3y-8)/12 = y/5 ?

multiply both sides by 60
5 (3y-8) = 12 y
15 y - 40 = 12 y
3 y = 40

check

[3(40/3) -8 ]/12 = (40/3)/5 ????
[ 40 -8 ] /12 = 8/3
32/12 = 8/3???
8/3 = 8/3 remarkable

To solve the equation (3y-8)/12 = y/5, we can follow these steps:

Step 1: Multiply both sides of the equation by the common multiple of the denominators 12 and 5, which is 60. This will eliminate the fractions.
(3y - 8)/12 * 60 = y/5 * 60

Step 2: Simplify each side of the equation.
(60 * (3y - 8))/12 = (60 * y)/5

Step 3: Simplify further.
(60/12) * (3y - 8) = (60/5) * y
5(3y - 8) = 12y

Step 4: Distribute the 5 on the left side of the equation.
15y - 40 = 12y

Step 5: Isolate the variable on one side of the equation by subtracting 12y from both sides.
15y - 12y - 40 = 12y - 12y
3y - 40 = 0

Step 6: Isolate the variable by adding 40 to both sides.
3y - 40 + 40 = 0 + 40
3y = 40

Step 7: Solve for y by dividing both sides by 3.
(3y)/3 = 40/3
y = 40/3

So, the solution to the equation is y = 40/3.