a bullet of mass 120g is fired horizontally into a fixed wooden block with a speed of 20 m/s. If the bullet is brought to rest in the block in 0.1s by a constant resistance, calculate the
1) magnitude of the
2) Distance moved by the bullet in the wood.?
1. V = Vo + a*t = 0.
20 + a*0.1 = 0,
a = -200 m/s^2.
F = M*a = 0.120 * (-200) = -24 N. = opposing resistance.
Thanks but can u break it down for me
Thanks but can you break it for me please
Tnx to but I need it in details please
a = ∆v/∆t = -20/0.1 = -200 m/s^2
s = vt + 1/2 at^2 = 20*0.1 - 100*0.1^2 = ?
To find the answers to these questions, we need to apply the principles of physics, specifically Newton's second law of motion and the equations of motion. Let's break it down step by step:
1) Magnitude of the constant resistance (force):
We can start by finding the force exerted on the bullet. According to Newton's second law of motion, force (F) is equal to mass (m) multiplied by acceleration (a). Since the bullet is brought to rest, the final velocity (v) is 0. We can rearrange the equation to solve for force:
F = m * a
The acceleration can be calculated using the equation:
a = (v - u) / t
Where:
v = final velocity (0 m/s)
u = initial velocity (20 m/s)
t = time taken (0.1 s)
Substituting these values in, we can find the acceleration:
a = (0 - 20) / 0.1
a = -200 m/s² (negative sign indicates deceleration)
Now, substitute the given mass of the bullet:
m = 120 g = 0.12 kg
F = 0.12 kg * -200 m/s²
F = -24 N
The magnitude of the constant resistance force exerted on the bullet is 24 Newtons (N).
2) Distance moved by the bullet in the wood:
We can use the equations of motion to find the distance moved by the bullet. In this case, as the bullet is brought to rest, the final velocity (v) is 0 m/s.
The equation we can use is:
v² = u² + 2as
Where:
u = initial velocity (20 m/s)
a = acceleration (-200 m/s²)
s = distance traveled
Rearranging the equation, we get:
s = (v² - u²) / 2a
Substitute the values:
s = (0² - 20²) / (2 * -200)
s = 400 / -400
s = -1 m (negative sign indicates direction opposite to initial velocity)
Therefore, the bullet travels a distance of 1 meter in the wood, opposite to its initial velocity.
To summarize:
1) The magnitude of the constant resistance force exerted on the bullet is 24 Newtons (N).
2) The bullet travels a distance of 1 meter in the wood, opposite to its initial velocity.