solid weight 20N air 15N density 0.8 calculat the volume of oil displaced
To calculate the volume of oil displaced, we can use Archimedes' principle, which states that the weight of the fluid displaced by an object is equal to the buoyant force acting on the object.
Given:
Weight of solid = 20 N
Weight of air = 15 N
Density of fluid (oil) = 0.8
First, let's calculate the weight of the solid in the oil:
Weight of solid in oil = Weight of solid - Weight of air
Weight of solid in oil = 20 N - 15 N
Weight of solid in oil = 5 N
Next, we can calculate the volume of oil displaced using the formula:
Volume of oil displaced = Weight of solid in oil / Density of fluid
Volume of oil displaced = 5 N / 0.8
Therefore, the volume of oil displaced is 6.25 cubic meters.
To calculate the volume of oil displaced, we need to use Archimedes' principle, which states that the buoyant force exerted on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
In this case, we have the weight of the solid (20 N) and the weight of the air (15 N). Therefore, the net weight or effective weight of the object in the fluid is (20 N - 15 N) = 5 N.
Now, let's assume that the density of the oil is ρ (rho) and the volume of oil displaced is V.
According to Archimedes' principle, the weight of the oil displaced is equal to the net weight of the solid:
Weight of oil displaced = Net weight of solid
Density of oil (ρ) × Volume of oil displaced (V) × gravitational acceleration (g) = Net weight of solid
Using the given information, let's calculate the volume of oil displaced:
Density of oil (0.8) × Volume of oil displaced (V) × gravitational acceleration (9.8 m/s^2) = 5 N
0.8 V × 9.8 = 5
7.84 V = 5
V = 5 / 7.84
V ≈ 0.6378 m^3
Therefore, the volume of oil displaced is approximately 0.6378 cubic meters.