show how 500ml of 2M H2SO4 can be prepared from a bottle of the acid with 95% purity(H=1, S=32, O=16, specific gravity of H2SO4 is 1.82

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  1. Calculate the M or the 95% bottle of H2SO4.
    1000 nK x 1,82 g/mL x 0.95 x 1 mol/98 g/mol = approx 18 that's an estimate.
    Then mL x M = mL x M is the dilution formula.
    500 mL x 2 M = ?mL x 18 M.
    Solve for ?mL. Add that ?mL of the 95% stuff to a 500 mL volumetric flask containing about 200 or 300 mL distilled water, then fill to the mark of the flask, mix thoroughly, stopper, label.
    Post your work if you get stuck.

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