How many electrons should be removed from the van de graaff generator so that its electric charge reaches 1.6 uC?
well, how many electrons in a Coulomb?
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To determine the number of electrons that should be removed from the Van de Graaff generator to reach an electric charge of 1.6 μC (microcoulombs), we need to know the elementary charge of an electron and the formula for calculating the charge.
The elementary charge of an electron is approximately -1.6 x 10^-19 coulombs (C). This value represents the magnitude of the charge on a single electron.
The formula to calculate the charge is:
Charge (Q) = Number of electrons (n) × Elementary charge (e)
Rearranging the formula, we have:
Number of electrons (n) = Charge (Q) / Elementary charge (e)
Now let's substitute the given values into the formula:
Charge (Q) = 1.6 x 10^-6 C (since 1 μC = 10^-6 C)
Elementary charge (e) = -1.6 x 10^-19 C
Number of electrons (n) = (1.6 x 10^-6 C) / (-1.6 x 10^-19 C)
Simplifying the expression, we can cancel out the units of charge:
Number of electrons (n) = (1.6 x 10^-6) / (1.6 x 10^-19)
Dividing the numerator by the denominator, we subtract the exponents:
Number of electrons (n) = 10^13
Therefore, approximately 10^13 (ten to the power of 13) electrons need to be removed from the Van de Graaff generator to reach an electric charge of 1.6 μC.