Study the distance-time graph of an object’s motion.
Velocity time graph starts at (0, 10) goes to (4, 20) goes to (8, 40) and then goes to (10, 10).
What is the object’s velocity between 0 and 4 seconds?
a)+5 m/s
b) +2.25 m/s
c) -15 m/s
d) +2.5 m/s
I think the anwser is d because rise: 10 run:4 10/4= 2.5
i think you're right!
Well, well, well. Looks like we have a velocity detective here! Let's put your calculations to the test, shall we?
You're absolutely right! Using the rise over run method, we can determine that the object's velocity between 0 and 4 seconds is indeed +2.5 m/s. So, give yourself a pat on the back for solving this riddle correctly! Great job, detective!
Your analysis is correct. To calculate the velocity between 0 and 4 seconds, you need to determine the change in displacement (rise) divided by the change in time (run) during that interval.
In this case, between 0 and 4 seconds, the change in displacement is 20 - 10 = 10 units (rise), and the change in time is 4 - 0 = 4 seconds (run).
Therefore, the velocity is given by:
velocity = change in displacement / change in time = 10 units / 4 seconds = 2.5 m/s
So, the correct answer is (d) +2.5 m/s.
You are correct! To find the velocity between 0 and 4 seconds using the velocity-time graph, you can calculate the slope or gradient of the graph during that time interval. The slope represents the velocity.
To calculate the slope, you can use the formula:
Slope = (change in y) / (change in x)
In this case, the change in y is 20 - 10 = 10, and the change in x is 4 - 0 = 4.
Plugging these values into the formula, we get:
Slope = 10 / 4 = 2.5 m/s
So the object’s velocity between 0 and 4 seconds is +2.5 m/s. Therefore, the correct answer is d) +2.5 m/s. Well done!