a rectangular container has a 10 cm square base and contain water to a depth of 12 cm. when a stone of a mass of 600g is gently lowered into the water, the level rises to 14 cm
umm ... the level started at 12 cm
volume = (14 - 12) * 10 * 10
volume of stone: 14*10*10 cm^3
density= mass/volume
200 centimetre cube
To find the volume of water displaced by the stone, we can use the equation:
Volume of water displaced = Final water level - Initial water level
The initial water level is given as 12 cm, and the final water level is given as 14 cm. Therefore:
Volume of water displaced = 14 cm - 12 cm = 2 cm^3
Now, if the volume of water displaced is equal to the volume of the stone, we can find the volume of the stone. Since the density of water is 1 g/cm^3, the volume of the stone (in cm^3) is equal to its mass (in grams).
Volume of stone = 600 g
Therefore, the volume of the stone is 600 cm^3.
Since the base of the container is a square with sides measuring 10 cm, the volume of the container can be determined by multiplying the base area by the height.
Volume of container = Base area x Height
= 10 cm x 10 cm x 12 cm
= 1200 cm^3
So, the volume of the container is 1200 cm^3.
To summarize:
- The volume of water displaced by the stone is 2 cm^3.
- The volume of the stone is 600 cm^3.
- The volume of the container is 1200 cm^3.