HELP
Find the solution for x,y.
In the problem...
5x-3y=-11
x-2y=2
Multiply the second equaton by five.
5x-3y=-11
5x-10y=10
subtract the second equation from the first.
7y=-21
solve for y, then put y into either of the beginning equations to solve for x.
To solve the system of equations:
1. Multiply the second equation by 5 to eliminate the coefficient of x:
5(x - 2y) = 5(2)
5x - 10y = 10
2. Now you have two equations:
5x - 3y = -11
5x - 10y = 10
3. Subtract the second equation from the first to eliminate x:
(5x - 3y) - (5x - 10y) = -11 - 10
5x - 3y - 5x + 10y = -21
7y = -21
4. Solve for y by dividing both sides of the equation by 7:
y = -21 / 7
y = -3
5. Substitute the value of y (-3) into either of the original equations to solve for x:
5x - 3(-3) = -11
5x + 9 = -11
5x = -11 - 9
5x = -20
x = -4
Therefore, the solution for the system of equations is x = -4 and y = -3.