1. The compound KICO3 decomposes according to the following equation:
2KCIO3 -> 2KCL + 3O2
a. what is the mole ratio of KCIO3 to O2 in this reaction?
b. How many moles of O2 can be produced by letting 6.0 moles of KCIO3 react based on the above equation?
c. how many molecules of oxygen gas, O2 are produced in question 1b?
a. Look at the numbers. You have 2 mols KClO3 and 3 mol O2.
b. 2 mols KClO3 = 3 mols O2; therefore, 6 mols KClO3 must produce 9 mols O2.
c. There are 6.02E23 molecules in 1 mole of anything.
To find the mole ratio of KCIO3 to O2, we compare the coefficients in the balanced chemical equation:
2KCIO3 -> 2KCL + 3O2
a. The mole ratio of KCIO3 to O2 is 2:3. This means that for every 2 moles of KCIO3, 3 moles of O2 are produced.
b. To determine the moles of O2 produced when 6.0 moles of KCIO3 react, we can set up a proportion using the mole ratio:
2 moles KCIO3 : 3 moles O2
6.0 moles KCIO3 : x moles O2
Cross-multiplying, we get:
(2 moles KCIO3)(x moles O2) = (6.0 moles KCIO3)(3 moles O2)
2x = 18
x = 9 moles O2
Therefore, 6.0 moles of KCIO3 would produce 9 moles of O2.
c. To find the number of molecules of O2 produced, we can use Avogadro's number.
1 mole of any substance contains 6.022 x 10^23 molecules.
Therefore, 9 moles of O2 can be calculated as:
9 moles O2 * (6.022 x 10^23 molecules O2/1 mole O2) = 5.4198 x 10^24 molecules O2
Hence, 6.0 moles of KCIO3 would produce approximately 5.42 x 10^24 molecules of O2.