A brass rod is 2.0 metres long at a certain temperature. What is its length for a temperature rise of 100 kilogram if the linear expansivity of brass is 10/10^5k^1?
To find the change in length of the brass rod due to a temperature rise, you need to use the formula for linear expansivity. The formula is:
ΔL = αLΔT
Where:
ΔL is the change in length of the brass rod
α is the linear expansivity of brass
L is the original length of the rod
ΔT is the change in temperature
In this case, the original length of the brass rod is given as 2.0 meters, the linear expansivity of brass is given as 10/10^5k^(-1), and the change in temperature is 100 Kelvin (not kilogram, as mentioned in the question).
Plugging in these values into the formula, we get:
ΔL = (10/10^5) * 2.0 * 100
Now let's calculate the result:
ΔL = (10/10^5) * 2.0 * 100
ΔL = (10/100000) * 2.0 * 100
ΔL = (1/10000) * 2.0 * 100
ΔL = 0.0002 * 200
ΔL = 0.04 meters
So, the change in length of the brass rod for a temperature rise of 100 Kelvin is 0.04 meters.