What is the equivalent weight of HCL in given reaction : k2cr2o7+14hcl=2kcl+2crcl3+3cl2+h2o
To determine the equivalent weight of HCl in the given reaction:
k2cr2o7 + 14HCl → 2KCl + 2CrCl3 + 3Cl2 + H2O
1. Start by writing down the balanced ionic equation for the reaction:
Cr2O7^2- + 14H+ + 6Cl- → 2Cr3+ + 6Cl2 + 7H2O + [K+] + [K+]
2. From the balanced equation, you can see that 1 mole of K2Cr2O7 reacts with 14 moles of HCl.
3. The equivalent weight is the molecular weight of the substance divided by its valence or the number of moles of substance that reacts or displaces one mole of hydrogen ions (H+).
4. The molecular weight of HCl is 36.46 g/mol. Since 1 mole of HCl reacts with 1 mole of H+ ions, the equivalent weight of HCl is also 36.46 g/mol.
Therefore, the equivalent weight of HCl in the given reaction is 36.46 g/mol.
What is molemassHCl/14?
Honestly, I am amazed someone is still teaching this.